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my inverter is small and only puts out 100 watts. but its all i need to power the small speakers. and by your formula: 100 watts / 12 = 8.33 then mulitplying that by 1.1 = 9.16 amp fuse needed, so basically a 10amp inline fuse is needed before the lighter?
what i dont get is how does this lower the amps? a fuse just breaks when a larger amperage passes through it. so how does the large amperage from the battery convert down to a smaller amperage to not blow all the electrics in the car?
im still in the learning process for car electronics, i been neglecting it for years...
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what I have:
1985 Gs:12a All motor Drag car - 1973 Rx2: Play car
What I had:
93 Touring: TRADED - 91 Coupe: TRADED - 90 GTU: RHD - 88 10AE: SOLD - 87 Base: SOLD - 86 Base: SOLD - 1985 GSLSE - 85 Gsl: SOLD - 80 Gs: TRADED - 1972 Rx2
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