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I am saying that the Rotary’s displacement is a physical and measurable size.
A poor example would be a 22 cal. rifle. If it fires twice is it a 44 cal? No its physical size stays the same. And that size is measurable.
Terms like: comparable, relative to, or sort of like, are great for helping others understand, but have no place in a scientific discussion .
For example, if you “cc” the Rotary’s combustion chamber at TDC and multiply that times the compression ratio. What would you expect the resultant displacement to be?
Or another example more to the point… I am doing some in-chamber testing… trying to optimize burn rate and pressure… we need the dimensions of the working parts…. the surface area of the rotor, the offset of the eccentric shaft, and the displacement for each degree of rotation. The changes of displacement will be compared to the actual pressure read by the pressure sensor. Then formulas convert this force to torque and in turn HP, VE, burn rate, location of peak pressure, etc.
What displacement do I use?
The three internet suggestions of the rotary displacement would yield: 500HP for 1300cc, or 1000HP for 2600cc, or 1500HP for the 3900cc.
Which should we use?
Barry
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