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Barry Bordes · 06-02-2011, 11:48 AM

Yes Peter I agree that it would take three revolutions of the eccentric shaft to have all faces of the rotor see fire.

Following that logic the other trochoid shapes would need four or five revolutions to show all faces and hence we would have to multiply them by 4 or 5.

I am saying that in all of these shapes that the displacement is the volume of the largest cavity created by the two corresponding surfaces (actually 4 counting end plates).

This would hold true for a two-stroke and a four-stroke also.

As an example the caliber of this revolver doesn't change if it holds different numbers of slugs. It is still a 357.

06-02-2011, 11:48 AM	#10
Barry Bordes Rotary Fanatic Join Date: Feb 2008 Location: Slidell, LA Posts: 191 Rep Power: 18	Yes Peter I agree that it would take three revolutions of the eccentric shaft to have all faces of the rotor see fire. Following that logic the other trochoid shapes would need four or five revolutions to show all faces and hence we would have to multiply them by 4 or 5. I am saying that in all of these shapes that the displacement is the volume of the largest cavity created by the two corresponding surfaces (actually 4 counting end plates). This would hold true for a two-stroke and a four-stroke also. As an example the caliber of this revolver doesn't change if it holds different numbers of slugs. It is still a 357.